Given the function f (x) = f '(π 4) cosx + SiNx, then the value of F (π 4) is______ ．

Because f ′ (x) = - F ′ (π 4) · SiNx + cosx, the solution of F ′ (π 4) = - F ′ (π 4) · sin π 4 + cos π 4 is f ′ (π 4) = 2-1, so f (π 4) = f ′ (π 4) cos π 4 + sin π 4 = 22 (2-1) + 22 = 1, so the answer is 1

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