Given the radius of ⊙ o OA = 5, the chord center distance OC of chord AB = 3, then AB = () A. 4B. 6C. 8D. 10

As shown in the figure: ∵ OC ⊥ AB, OC = 3, OA = 5, ∵ AB = 2Ac, ∵ AC = oa2 − oc2 = 52 − 32 = 4, ∵ AB = 2Ac = 8

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1. OC in circle O is perpendicular to ab AB = 16 sinaoc = 3 / 5 calculate radius OA of circle O and chord center distance OC calculate cosaoc tanaoc
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