As shown in the figure, it is known that in RT △ ABC, the radius of the inscribed circle is 3cm and the radius of the circumscribed circle is 12.5cm, so the three sides of △ ABC can be calculated

In RT △ ABC, the radius of the inscribed circle is 3cm, the radius of the circumscribed circle is 12.5cm, ab = 25cm, CE = CF = 3cm, be = BD, AF = ad, if be = x, then BD = x, ad = AF = 25-x, ｜ BC2 + ac2 = AB2, ｜ (x + 3) 2 + (3 + 25-x) 2 = 252, the solution is: x = 4 or 21, ｜ be = 4 or 21

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1. As shown in the figure, circle O is the inscribed circle of triangle ABC, and the tangent points are D, e, F. the known angles BCA = 90 degrees, ad = 5cm, DB = 3cm. Find the area of triangle ABC D is on AB, e is on BC, f is on AC
2. If the side length of equilateral △ ABC is 3cm, the radius of its inscribed circle is
3. As shown in the figure, the radius of the inscribed circle of RT △ ABC is 1 cm, and the hypotenuse is tangent to the circle O at point D. given AB = 5, find the length of AD and AC
4. As shown in the figure, BD is the diameter of ⊙ o, OA ⊥ ob, M is the point on the inferior arc AB, through point m as the tangent of ⊙ o, the extension line of OA at point P, MD and OA at point n. (1) verification: PM = PN; (2) if BD = 4, PA = 32ao, through point B as BC ∥ MP intersection ⊙ o at point C, the length of BC
5. As shown in the figure, BD is the diameter of ⊙ o, OA ⊥ ob, M is the point on the inferior arc AB, through point m as the tangent of ⊙ o, the extension line of OA at point P, MD and OA at point n. (1) verification: PM = PN; (2) if BD = 4, PA = 32ao, through point B as BC ∥ MP intersection ⊙ o at point C, the length of BC
6. As shown in the figure, the center of two concentric circles is O, the radius of big circle O is OA, OB intersects small circle O with C, D, please explain: AB / / CD I hope we don't use center angle and circle angle
7. As shown in the figure, in the two concentric circles with o as the center, the chord AB and CD of the big circle are equal, and AB and the small circle are tangent at point E
8. As shown in the figure, it is known that in △ AOB, ∠ AOB = 90 ° OD ⊥ AB is at point D. the circle with point o as the center and OD as the radius intersects OA at point E, intercept BC = ob on Ba, and prove that CE is the tangent of ⊙ o
9. As shown in the figure, ⊙ o radius OA is the diameter of ⊙ O1, ⊙ o another radius OC intersection ⊙ O1 and point B, try to explain the arc length relationship between chord AB and chord AC
10. As shown in the figure, OA, ob, OC are ⊙ o radius - AC = - BC, D, e are OA, ob, are the midpoint CD and CE equal? Why is it as shown in the figure
11. The diameter of the circle O of BD, OA perpendicular to ob, M is a point on the inferior arc AB, the tangent MP of the circle O crosses through point m, the extension line of OA intersects at point P, and the intersection of MD and OA intersects at point n 1. Verify PM = PN. 2. If BD = 4, PA = two-thirds Ao, make BC ∥ MP through point B, intersect circle O at point C, and find the length of BC.
12. OC in circle O is perpendicular to ab AB = 16 sinaoc = 3 / 5 calculate radius OA of circle O and chord center distance OC calculate cosaoc tanaoc
13. Given the radius of ⊙ o OA = 5, the chord center distance OC of chord AB = 3, then AB = () A. 4B. 6C. 8D. 10
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18. The analytic expression of the straight line y = - 3x + 1 is obtained by moving up one unit, and then moving right three units
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