It is known that Y1 is positively proportional to X (scale coefficient is K1), Y2 is inversely proportional to X (scale coefficient K2), If the image of function y = Y1 + Y2 passes through point (1,10) (2, - 1), then what is y = when x = 7? | Math enthusiast | Mathematical art

It is known that Y1 is positively proportional to X (scale coefficient is K1), Y2 is inversely proportional to X (scale coefficient K2), If the image of function y = Y1 + Y2 passes through point (1,10) (2, - 1), then what is y = when x = 7?

Let Y1 = K1 * X
y2=k2/x
Because y = Y1 + Y2
So y = K1 * x + K2 / X ①
When x = 1, y = 10, substituting into Formula 1, we get
10=k1+k2②
When x = 2, y = - 1, substituting into Formula 1, we get
-1=2k1+k2/2③
The solution of simultaneous
k1=-4,k2=14
So y = - 4x + 14 / X
When x = 7, y = - 4 * 7 + 14 / 7 = - 26
Hope to adopt

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