Given the quadratic function y = a (x + k) 2 + K, no matter what the value of K is, the vertex of the function image is always in the A. Y = X. B. y = - X. C. X axis. D. Y axis, friendly tips; do not answer, to the whole process Oh!

Given the quadratic function y = a (x + k) 2 + K, no matter what the value of K is, the vertex of the function image is always in the A. Y = X. B. y = - X. C. X axis. D. Y axis, friendly tips; do not answer, to the whole process Oh!

The x value or y value of the function at the vertex is the maximum or minimum, y = a (x + k) & sup2; + K (1) when y is the maximum or minimum, (x + k) & sup2; = 0, we get x = - K, then y = a (x + k) & sup2; + k = a (- K + k) + k = k, so y = - x (2) when x is the maximum or minimum, y = a (x + k) & sup2; + K (Y-K) / a = (x + k) & sup2