When x = 3, the minimum value of y = - 1, and the image is over (0,7), the analytic expression of quadratic function of Y with respect to X is obtained
When x = 3, the minimum value of y = - 1
Then vertex (3, - 1)
So y = a (x-3) & sup2; - 1
Over (0,7)
So 7 = a (0-3) & sup2; - 1
a=8/9
So y = 8x & sup2 / 9-16x / 3 + 7
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