Given that the function f (x) = log (2∧x-1) (a > 0, and a ≠ 1) always has f (x) > 0 in the interval (0,1), then the monotone increasing interval of the function y = log ∨ a (X & # 178; - 2x-3) is

Given that the function f (x) = log (2∧x-1) (a > 0, and a ≠ 1) always has f (x) > 0 in the interval (0,1), then the monotone increasing interval of the function y = log ∨ a (X & # 178; - 2x-3) is

If x is in the interval (0,1), then 2 ^ X-1 belongs to (0,1), then f (x) = log a (2 ^ x-1), and if f (x) > 0, then 0