The inverse function f ^ - 1 (x) = () of function f (x) = log (2) (1 + 1 / x) (x > 0) | Math enthusiast | Mathematical art

The inverse function f ^ - 1 (x) = () of function f (x) = log (2) (1 + 1 / x) (x > 0)

Let y = log2 (1 + 1 / x). When x > 0, Y > log2 (1) = 0
The inverse solution is 1 + 1 / x = 2 ^ y
x=1/(2^y-1)
So the inverse function is y = 1 / (2 ^ x-1), x > 0

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