It is known that the image of the first-order function y = 3x + 3 intersects with the x-axis at point a and the y-axis intersects with point B, and the image of the second-order function y = - x ^ 2 + BX + C passes through two points a and B 1) There is a point m on the parabola, so that the area of △ mAb is equal to the area of △ OAB, and the coordinates of point m are obtained 2) On the line AB, there is a point P passing through P, making a parabola at the intersection of L / / X axis and C D (C is on the left side of D). If PC + PD = 6, find the coordinates of point P

It is known that the image of the first-order function y = 3x + 3 intersects with the x-axis at point a and the y-axis intersects with point B, and the image of the second-order function y = - x ^ 2 + BX + C passes through two points a and B 1) There is a point m on the parabola, so that the area of △ mAb is equal to the area of △ OAB, and the coordinates of point m are obtained 2) On the line AB, there is a point P passing through P, making a parabola at the intersection of L / / X axis and C D (C is on the left side of D). If PC + PD = 6, find the coordinates of point P

Answer: 1) the intersection of y = 3x + 3 and the coordinate axis a (- 1,0), B (0,3) is substituted into the parabola y = - X & # 178; + BX + C is: - 1-B + C = 0-0 + 0 + C = 3, the solution is: B = 2, C = 3, the parabola is y = - X & # 178; + 2x + 3, because: s △ mAb = s △ OAB, so: the distance from point m and point O to AB is equal, so: Mo / / AB, so: the straight line Mo is y