If the inverse function of F (x) = (2x-1) / (x + a) is itself, then the value of a is

∵ f (x) = (2x-1) / (x + a), ∵ (x + a) f (x) = 2x-1, ∵ XF (x) + AF (x) = 2x-1, ∵ 2-F (x)] x = 1 + AF (x), ∵ x = [1 + AF (x)] / [2-F (x)]. The inverse function of the function f (x) = (2x-1) / (x + a) is f (x) = (1 + ax

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