On the roots of equations and zeros of functions If the square-x-1 = 0 of equation 2aX has exactly one solution in (0,1), then what is the value range of a?
Let f (x) = 2aX ^ 2-x-1
When a = 0, it is obviously not suitable
When a ≠ 0, then
f(0)·f(1)=-1×(2a-2)
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