As shown in the figure, the triangle ABC is a right triangle, and the quadrilateral befd is a square. Given that the lengths of AB and BC are 12 cm and 20 cm respectively, what is the square area?
Connect BF,
The area of △ ABC is 12 × 20 △ 2 = 120 square centimeters
The area sum of △ ABF and △ BCF is 120 square centimeters
Because DF = EF, EF = 120 × 2 ^ (12 + 20) = 7.5cm
The square area is 7.5 × 7.5 = 56.25 square centimeters
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