In triangle ABC, D and E are the midpoint of AB and AC respectively, then the area ratio of triangle ade to quadrilateral DEBC is ()
In triangle ABC, D and E are the midpoint of AB and AC respectively, then the area ratio of triangle ade to quadrilateral DEBC is (1:3)
Triangle ade is similar to triangle ABC, and the similarity ratio is 1:2
Then the area of triangle ade: the area of triangle ABC = 1:4
That is: Triangle ade area: quadrilateral DEBC area = 1: (4-1) = 1:3
RELATED INFORMATIONS
- 1. It is known that in ABC triangle, D and E are AC = 7, ∠ ABC = 120 °, AE = BC and Sina = 3 √ 3 / 14 on AC and ab respectively, and the area of quadrilateral DEBC is calculated Please, the sooner the better,
- 2. As shown in the figure, in △ ABC, ∠ C = 90 ° de bisects AB vertically, intersects BC with E, ab = 20, AC = 12. (1) find the length of be; (2) find the area of quadrilateral Adec
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- 4. As shown in the figure, fold the △ ABC paper along de. when point a falls inside the quadrilateral bced, try to explore,
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- 6. As shown in the figure, fold a triangular piece of paper ABC along De, and point a falls inside the quadrilateral bced (1). If ∠ a = α, find ∠ 1 + 2
- 7. It is known that, as shown in the figure, in triangle ABC de / / BC, and the area of triangle ABC is equal to the area of trapezoid bced, the ratio of De to BC is calculated
- 8. As shown in the figure, in RT △ ABC, the area sum of square Adec and square bcfg is () A. 150cm2b. 200cm2c. 225cm2d. Unable to calculate
- 9. As shown in the figure, make a square from the three sides of RT △ ABC. If the side length of the largest square is 8cm, then the sum of the areas of square m and square n is______ cm2.
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- 16. As shown in the figure, in the right triangle ABC, e is the intersection of the bisectors of two acute angles, ed ⊥ BC is D, EF ⊥ AC is F. can you explain that the quadrilateral cdef is a square?
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- 18. As shown in the figure, in the right triangle ABC, the quadrilateral efbh is a square, ab = 21cm, BC = 28cm, AC = 35cm, ED is perpendicular to AC, ed = 8.4cm, what is the area of the square efbh?
- 19. In △ ABC, ∠ ACB = 90 °, De is the median line of △ ABC, point F is on the extension line of BC, and ∠ CDF = ∠ a
- 20. In △ ABC, ∠ BCA = 90 degrees, D and E are the middle points on the sides of AC and ab respectively, f is on the extension line of BC, ∠ CDF = ∠ a It's a proof