As shown in the figure, in the triangle ABC, the bisector of angle ABC and angle ACB intersects at point O, passes through the point and makes EF parallel BC, intersects AB at e, intersects AC at F, and △ AB As shown in the figure, in the triangle ABC, the bisector of the angle ABC and the angle ACB intersects at the point O, passes through the point for EF parallel BC, intersects AB at e, intersects AC at F, and △ ab.% d% a as shown in the figure, in the triangle ABC, the bisector of the angle ABC and the angle ACB intersects at the point O, passes through the point for EF parallel BC, intersects AB at e, intersects AC at F, and the perimeter of △ ABC is 24cm, BC = 10cm, calculate the perimeter of the triangle AEF

As shown in the figure, in the triangle ABC, the bisector of angle ABC and angle ACB intersects at point O, passes through the point and makes EF parallel BC, intersects AB at e, intersects AC at F, and △ AB As shown in the figure, in the triangle ABC, the bisector of the angle ABC and the angle ACB intersects at the point O, passes through the point for EF parallel BC, intersects AB at e, intersects AC at F, and △ ab.% d% a as shown in the figure, in the triangle ABC, the bisector of the angle ABC and the angle ACB intersects at the point O, passes through the point for EF parallel BC, intersects AB at e, intersects AC at F, and the perimeter of △ ABC is 24cm, BC = 10cm, calculate the perimeter of the triangle AEF

According to the meaning of the title, ∠ EBO = ∠ CBO, ∠ FCO = ∠ BCO ∵ EF is parallel to BC, then ∠ EOB = ∠ CBO, ∠ FOC = ∠ BCO ∵ EBO = ∠ EOB, ∠ FCO = ∠ FOC. Therefore, be = EO, of = FC ∵ AE + EB + BC + CF + FA = 24, that is, AE + EO + BC + of + FA = 24, AE + EO + of + FA = 14 is the perimeter of triangle AEF, so the answer is 14cm