It is known that in △ ABC, ∠ a = 60 ° and the bisectors of ∠ ABC and ∠ ACB intersect at point O, then the degree of ∠ BOC is 0______ Degree

∵∠A=60°∴∠ABC+∠ACB=120°∴∠BOC=180°-12（∠ABC+∠ACB）=120°．

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