In △ ABC, ad, be and CF are bisectors of three internal angles respectively, which intersect at O and og ⊥ BC, and the perpendicular foot is g Same topic
prove:
∵∠ BOD = ∠ ABO + ∠ Bao = ∠ BAC / 2 + ∠ ABC / 2 = (180 degrees - ∠ ACB) / 2 = 90 degrees - ∠ ACB / 2
=90 degrees - OCB
∠ GOC = 90 degrees - ∠ OCB
∴∠BOD=∠GOC
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