Given that the coordinates of the three vertices of the triangle ABC are a (- 2,1), B (3,6), C (6,5), the equation of the circumcircle of the triangle ABC is obtained

The slope of the line lac is KAC = (5-1) / (6 + 2) = 1 / 2, the slope of the vertical bisector k'ac = - 1 / KAC = - 2, the coordinates of the midpoint of AC are (2,3), the equation of the vertical bisector of AC is Y-3 = - 2 (X-2), the slope of the line LBC is KBC = (5-6) / (6-3) = - 1 / 3, and the slope of the vertical bisector k'bc = - 1 / KB

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