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In ABC, a > C > b, and C = a + B / 2, if vertex a (- 1,0) B (1,0), find the trajectory equation of vertex C
If Ca + CB = 2Ab = 4 and C is not on the straight line AB, then C is on the ellipse with half focal length of 1, long half axis of 2 and short half axis of root 3, except the intersection point with X axis. That is to say, the trajectory equation of C is x ^ 2 / 4 + y ^ 2 / 3 = 1 (y is not equal to 0) and CB > AB > AC, so C can only be on the left part of ellipse, that is, the trajectory equation of C is x ^ 2 / 4 + y ^ 2 / 3 = 1 (y is not equal to 0, X is not equal to 0)
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