As shown in the figure, in △ ABC, the bisectors of ∠ ABC and ∠ ACB intersect at point D, EF passes through point D and ef ‖ BC intersects AB at point E and AC at point F respectively. If AB = 10cm and AC = 8cm, calculate the perimeter of △ AEF
In ∫ EF ∥ BC, ∫ EDB = ∫ DBC, ∫ FDC = ∫ DCB, ∫ ABC, bisectors of ∫ ABC and ∫ ACB intersect at point D, ∫ EBD = ∫ DBC, ∫ FCD = ∫ DCB, ∫ EDB = ∫ EBD, ∫ FDC = ∫ FCD, ∫ ed = EB, FD = FC, ∫ AB = 10cm, AC = 8cm, the perimeter of ∫ AEF is AE + EF + AF = AE + ed + FD + AF = AE + EB + FC + AF = AB + AC = 10 + 8 = 18 (CM)
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