Let a vertex of △ ABC be a (3, - 1), the bisector equations of ∠ B and ∠ C be x = 0 and y = x respectively, and then the equation of the straight line BC is obtained | Math enthusiast | Mathematical art

Let a vertex of △ ABC be a (3, - 1), the bisector equations of ∠ B and ∠ C be x = 0 and y = x respectively, and then the equation of the straight line BC is obtained

The bisectors of ∵ - B and ∵ C are x = 0, y = x, AB and BC are symmetric for x = 0, AC and BC are symmetric for y = X. then a (3, - 1) symmetric point a '(- 3, - 1) about x = 0 is on the straight line BC, and a ″ (- 1,3) symmetric point a about y = x is also on the straight line BC. From the two-point formula, y − 3 − 1 − 3 = x − (− 1) − 3 − (− 1), the equation of the straight line BC is 2x y + 5 = 0

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