As shown in the figure, AE bisects ∠ BAC, BD = DC, de ⊥ BC, EM ⊥ AB, en ⊥ AC
It is proved that: connect be and EC, ∵ BD = DC, de ⊥ BC ∵ be = EC. ∵ AE bisection ≁ BAC, EM ⊥ AB, en ⊥ AC, EM = en, ≁ EMB = ≁ enc = 90 °. Be = EC, EM = enbe = ECEM = en, ≌ RT ≌ RT ≌ RT ≌ CNE (HL) ≁ BM = CN
RELATED INFORMATIONS
- 1. As shown in the figure, AE bisects ∠ BAC, BD = DC, de ⊥ BC, EM ⊥ AB, en ⊥ AC
- 2. In the RT triangle ABC, the angle B = 90 ° ED is the vertical bisector of AC, intersecting BC and AC at points E and D respectively, connecting AE, if the angle BAE: the angle BAC = 1:5
- 3. It is known that in △ ABC, D is the midpoint of AB, e is the point on AC, EF ‖ AB, DF ‖ be. (1) conjecture: the relationship between DF and AE is______ Try to explain the correctness of your conjecture
- 4. In the triangle ABC, point O is a moving point on the side of AC. when passing through point O, a straight line Mn is parallel to BC. Let the bisector of the intersection angle BCA of Mn be at e, and the bisector of the intersection angle BCA be at E Bisector at point F. (1) proof; EO = fo, (2) when point O moves to where, quadrilateral aecf is rectangular, prove your conclusion
- 5. As shown in the figure, in △ ABC & nbsp;, point O is a moving point on the edge of AC, and a straight line Mn ‖ BC is made through point O. suppose that the angular bisector of Mn intersecting ∠ BCA is at point E, and the outer angular bisector of intersecting ∠ BCA is at point F. (1) try to explain EO = fo; (2) when point O moves to where, is the quadrilateral aecf rectangular? (3) when the point O moves to where, and what condition does △ ABC satisfy, the quadrilateral aecf is a square? And explain the reason
- 6. As shown in the figure, in the triangle ABC, point O is a moving point on the side of AC. a straight line Mn is parallel to BC through point O, and the bisector of Mn ∠ BCA is set at point E, The bisector of the outer angle of intersection ∠ BCA is at point F (1) try to explain: EO = fo; (2) when point 0 moves to where, the quadrilateral aecf is a rectangle? And explain the reason
- 7. As shown in the figure, in the triangle ABC, point O is a moving point on the edge of AC, and a straight line Mn is parallel to BC through point O. suppose that the bisector of the intersection angle BCA of Mn is at point E, and the bisector of the external angle BCA of Mn is at point F. if CE = 12, CF = 5, the length of OC can be obtained
- 8. In △ ABC, point P is a moving point on edge AC, and a straight line Mn ∥ BC is made through point P. let Mn intersect ∥ BCA and its outer angle bisector be at point E, and intersect ∥ BCA and its outer angle be at point F (1) Verification: PE = PF (2) Can the quadrilateral BCFE be a diamond when point P moves on edge AC? Explain why (3) If there is a point P on the side of AC, let the quadrilateral aecf be a square, and AP / BC = (√ 3) / 2
- 9. In △ ABC, point O is a moving point on edge AC, and a straight line Mn parallel to BC is made through O. let Mn intersect the bisector of ∠ BCA at point e. the bisector of the outer angle of ∠ BCA intersects with point F 1. When point O moves on edge AC, will the quadrilateral BCFE be a diamond? If so, please prove. If not, explain the reason; 2. When point O moves to where, and △ ABC satisfies what conditions, the quadrilateral aecf is a square?
- 10. As shown in the figure, △ ABC, point O is a moving point on the edge of AC. make a straight line Mn ‖ BC through point O. let the bisector of the intersection angle BCA of Mn be at point E, and the bisector of the external angle ACD of △ ABC be at point F (1) Try to explain the line segment EO = fo (2) Guess: when point O moves to where, the quadrilateral aecf is a rectangle? And explain the reason
- 11. As shown in the figure, AE bisects ∠ BAC, BD = DC, de ⊥ BC, EM ⊥ AB, en ⊥ AC
- 12. As shown in the figure, AE bisects ∠ BAC, BD = DC, de ⊥ BC, EM ⊥ AB, en ⊥ AC
- 13. In △ ABC, ab = AC, ∠ B = 30 °, the vertical bisector EF of AB intersects AB at point E and BC at point F. if CF = 6 cm, then BF =? Cm
- 14. As shown in the figure, in △ ABC, ab = AC, ∠ B = 30 °, the vertical bisector EF of AB intersects AB at point E, BC at point F, EF = 2, then the length of BC is______ .
- 15. In the triangle ABC, the angle BAC = 135 degrees, Fe and GH are the vertical bisectors on both sides of AB and AC respectively, and intersect with BC at points E and G to find the degree of angle EAG
- 16. As shown in Figure 6, in △ ABC, the vertical bisector Mn of ∠ a = 105 ° AC intersects at point n, AC intersects at point m, and ab + BN = BC,
- 17. As shown in the figure, ABC = ADC = 90 °, M is the midpoint of AC, Mn ⊥ BD and N, and BN = nd is proved ditto
- 18. As shown in the figure, it is known that in △ ABC, the bisector of ∠ ABC intersects with the vertical bisector of AC side at point n, passing through point n makes nd ⊥ AB at D, NE ⊥ BC at e, and proves ad = C Verification: ad = CE
- 19. Known: as shown in the figure, BD is the angular bisector of △ ABC, EF is the vertical bisector of BD, and intersects AB at e and BC at point F
- 20. Known: as shown in the figure, BD is the angular bisector of △ ABC, EF is the vertical bisector of BD, and intersects AB at e and BC at point F