AB: de = BC: EF = CA: FD = 6:5, the difference between the perimeter of triangle ABC and triangle DEF is 4, how much is the perimeter of ABC and def?

∵ the circumference ratio of similar triangles is only equal to the similarity ratio Cabc:Cdef=6 Let the perimeter of def be x, then the perimeter of ABC is 6 / 5x. According to the meaning of the title, the equation is 6 / 5x - x = 4, x = 20 ﹥ the perimeter of DEF is 20 ﹥ ABC = 6 / 5x = 6 / 5 × 20 = 120

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1. In △ ABC and △ def, ABDE = BCEF = CAFD = 23, the perimeter of △ ABC is 13cm, then the perimeter of △ DEF is 13cm______ ．
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