As shown in the figure △ ABC, ad ⊥ BC, be ⊥ AC, BF = AC, if ∠ EBC = 25 °, then ∠ ACF=______ .
∨ ad ⊥ BC, be ⊥ AC, ∨ ADC = ∨ BDF = ∨ bea = 90 °, ∨ FBD + ∨ BFD = 90 °, ∨ DAC + ∨ AFE = 90 °, ∨ AFE = ∨ BFD, ∨ FBD = ∨ DAC = 25 ° in △ BDF and △ ADC, ∨ BDF = ∨ ADC ∨ DBF = ∨ dacbf = AC, ∨ BDF ≌ ADC (AAS), ∨ DF = DC
RELATED INFORMATIONS
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- 2. As shown in the figure, ad and be are the heights of BC and AC respectively in ABC
- 3. In triangle ABC, ad is perpendicular to BC and D, be is the middle line, and the angle EBC is 30 degrees
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- 7. As shown in the figure, BD is divided into two parts, be is divided into ABC 2:5, DBE = 21 ° and the degree of ABC is calculated
- 8. As shown in the figure, BD is divided into two parts, be is divided into ABC 2:5, DBE = 21 ° and the degree of ABC is calculated
- 9. Given that the point C is any point on the line AB (C does not coincide with a or b), AC and BC are taken as sides respectively, and the equilateral triangle ACD and equilateral △ BCE, AE and C are made on the same side of ab D intersects with m, BD intersects with CE with n The results show that: (1) ace ≌ DCB; (2) ACM ≌ DCN; (3) Mn ∥ ab
- 10. C is a point on the line AB, with AC and BC as edges, make equilateral △ ACD and equilateral △ BCE on the same side of AB, AE and CD intersect at m, BD and CE intersect at n It is proved that (1) △ MCN is an equilateral triangle. (2) if AC: CB = 2:1, then de ⊥ CE
- 11. As shown in the figure, D is a point inside the triangle ABC, connecting BD and ad, taking BC as the edge, making an angle outside the triangle ABC, CBE = angle abd, BCE = angle bad, be, CE intersecting at point E, connecting de. prove that the triangle DBE is similar to the triangle ABC
- 12. It is known that, as shown in the figure, D is a point inside △ ABC connecting BD and ad, with BC as the edge, outside △ ABC, make ﹥ CBE = ﹥ abd, ﹥ BCE = ﹥ bad, be and CE cross to e, connecting de. (1) verification: bcab = bebd; (2) verification: ﹥ DBE ﹥ ABC
- 13. As shown in the figure, in △ ABC, point E is on AB, point D is on BC, BD = be, ∠ bad = ∠ BCE, ad and CE intersect at point F. try to judge the shape of △ AFC and explain the reason
- 14. In the triangle ABC, ab = AC, BD = DC, take any point E in ad to judge the relationship between be and EC
- 15. As shown in the figure, in the linear triangle ABC, ∠ C = 90 °, BD is the angular bisector of △ ABC, be is the angular bisector of △ BDA, DF is the height of △ BDE
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- 17. The two right sides of a right triangle are 60cm and 80cm respectively. How many square centimeters is its area? The hypotenuse of this triangle is 100cm long. How high is the hypotenuse?
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