In triangle ABC, ad is perpendicular to BC and D, be is the middle line, and the angle EBC is 30 degrees

In triangle ABC, ad is perpendicular to BC and D, be is the middle line, and the angle EBC is 30 degrees

If a straight line EF is made through point E and perpendicular to BC, then EF is parallel to ad, because point E is the midpoint, so EF = 1 / 2ad, and because the angle EBC = 30 degrees, ad is perpendicular to BC, so EF = 1 / 2be, ad = be can be deduced