As shown in the figure, in the triangle ABC, angle a = 60 °, BD and CE bisect angle ABC and angle ACB respectively, BD and CE intersect at point O, try to judge the quantitative relationship of be, CD and BC and prove it

As shown in the figure, in the triangle ABC, angle a = 60 °, BD and CE bisect angle ABC and angle ACB respectively, BD and CE intersect at point O, try to judge the quantitative relationship of be, CD and BC and prove it

BC = be + CD. [prove] take a point F on BC, so that ∠ BOF = be. ······ ① there are obviously: ∠ BOE = OBC + OCB = (1 / 2) (∠ ABC + ACB) = (1 / 2) (180 ° - a) =