There is a point O in the equilateral triangle ABC, the angle AOB = 113 ° and the angle BOC = 123 ° to find the degree of the three internal angles of the triangle with AO, Bo and CO as sides

There is a point O in the equilateral triangle ABC, the angle AOB = 113 ° and the angle BOC = 123 ° to find the degree of the three internal angles of the triangle with AO, Bo and CO as sides

Rotate the triangle AOC clockwise to make AC coincide with AB, and point O turns to point O1;
Because Ao = AO1 and oao1 = 60 degrees, the triangle oao1 is an equilateral triangle,
The triangle obo1 is a triangle composed of OA, OB and OC,
Its three internal angles are: 113-60 = 53 degrees, 124-60 = 64 degrees, 180-53-64 = 63 degrees
No drawing,