Given that OA = (- 1,8) ob = (- 4,1) OC = (1,3) in the rectangular coordinate plane, it is proved that △ ABC is an isosceles triangle

Given that OA = (- 1,8) ob = (- 4,1) OC = (1,3) in the rectangular coordinate plane, it is proved that △ ABC is an isosceles triangle

The length between ab can be calculated by the formula of distance between points: under the root sign {(1-8) square + [- 4 - (- 1)] square} = under the root sign 58
The length of BC can also be calculated as 29 under the root sign
The length of AC is 29 under the root
bc=ac
So the two sides are equal and they are isosceles triangles