As shown in the figure, in the triangle ABC, ab = AC, the angle a = 120 ° de bisects AB and BC vertically in D, e

As shown in the figure, in the triangle ABC, ab = AC, the angle a = 120 ° de bisects AB and BC vertically in D, e

Because it is an isosceles triangle with an angle of 120 degrees, the base angle is 30 degrees, so the triangle BDE is a right triangle with an angle of 30 degrees, so let de length be x, then be = AE = 2x, BD = ad = (radical 3) x, so AC = (double radical 3) X
Because angle B = angle EAB = 30 degrees, so angle EAC = 90 degrees, so triangle AEC is right triangle, angle c is 30 degrees, so CE = 2 * AE = 4x
So CE = 4de