Equilateral triangle ABC, P is a point in the triangle, PA is equal to 3, Pb is equal to 5, PC is equal to 4, find the degree of ∠ APC

Equilateral triangle ABC, P is a point in the triangle, PA is equal to 3, Pb is equal to 5, PC is equal to 4, find the degree of ∠ APC

Rotate △ APC anticlockwise around point C to △ bp'c, connect PP ', so ∠ APC = bp'c, BP' = BP = 3, obviously △ CPP 'is equilateral triangle, so ∠ pp'c = 60, PC = PP' = 4, in △ BPP ', BP = 5, PP' = 4, BP '= 3, BP ^ 2 = PP' ^ 2 + PP '^ 2, so △ BPP' is right triangle, so ∠ BP'p = 90 °, so ∠ B