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As shown in the figure, in RT △ ABC, if ∠ C = 90 °, a = 30 °, e is the point on AB, AE: EB = 4:1, EF ⊥ AC is in F, and FB is connected, then the value of Tan ⊥ CFB is equal to () A. 33B. 233C. 533D. 53
According to the meaning of the question: in RT △ ABC, ∠ C = 90 °, ∠ a = 30 °, ∵ EF ⊥ AC, ∥ EF ∥ BC, ∵ cfac = BEAB ∵ AE: EB = 4:1, ∵ abeb = 5, ∥ AFAC = 45, let AB = 2x, then BC = x, AC = 3x
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