As shown in the figure, known angle AOB = 90 degrees, angle AOC is acute angle, OD bisecting angle BOC, OE bisecting angle AOC, calculate the degree of angle doe

forty-five
Sub OC is discussed inside and outside of AOB
The answer remains the same

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11. As shown in the figure, the known angle AOB = 90 degrees, the angle AOC is the acute angle. Od bisecting angle AOC, OE bisecting angle BOC. Calculate the degree of the angle doe? When the angle AOB = m degrees, the angle doe? Degree
12. The angle AOB = 80 degrees, OC is a ray outside the angle AOB, OD bisects the angle BOC, OE bisects the angle AOC, and the angle DOE needs geometric language There is another problem If the angle AOB = 80 degrees is changed to angle AOB = a degrees, what is the law obtained by finding ∠ doe?
13. It is known that the ray OC is in the interior of horizontal angle ∠ AOB, and ∠ AOC ＞ BOC, OD bisection ∠ AOC, OE bisection ∠ BOC ① Compare the values of ∠ COD and ∠ Coe ② Can you find out the size of ∠ doe? If so, find out its degree; if not, please explain the reason Thanks for the process
14. As shown in the figure: given ABO = 60, OC is the bisector of AOB, OD and OE bisector BOC and AOC respectively. When OC rotates around o point in AOB, ask if the degree of DOE is the same as before? Through this process, what conclusion do you come to?
15. In the triangle ABC, the angle B is 90 degrees, the point O is the intersection of the bisectors of the three angles of the triangle ABC, OE is vertical AB, of is vertical AC, O is vertical AB, O is vertical AC, O is vertical AC, O is vertical AB, O is vertical AC, O is vertical AC, O is vertical AC, O is vertical AC, O is vertical AC, O is d. E, f are perpendicular feet, BC = 16cm, ab = 12cm, find the distance from point O to three sides AB, AC, BC
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17. As shown in the figure, the triangle ABC is divided into two parts, AE = 3, EC = 2, BD = 3, DC = 1. What is the area ratio of the two parts
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