It is known that the ray OC is in the interior of horizontal angle ∠ AOB, and ∠ AOC > BOC, OD bisection ∠ AOC, OE bisection ∠ BOC ① Compare the values of ∠ COD and ∠ Coe ② Can you find out the size of ∠ doe? If so, find out its degree; if not, please explain the reason Thanks for the process
Because od bisects ∠ AOC and OE bisects ∠ BOC, so ∠ cod = 1 / 2 ∠ AOC and ∠ COE = 1 / 2 ∠ BOC
Because of ∠ AOC > BOC, so ∠ cod > Coe
∠DOE=∠COD+∠COE=1/2∠AOC+1/2∠BOC=1/2∠AOB
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