In triangle ABC, the angle BAC equals 135 degrees, ad is vertical to BC, the perpendicular foot is D, BD equals 4, CD equals 6, and the area of triangle ABC is calculated

&So AC ^ 2 / BC ^ 2 = ad ^ 2 / be ^ 2 (6 ^ 2 + x ^ 2) / (4 + 6) ^ 2 = x ^ 2 / [(4 ^ 2 + x ^ 2) / 2] (36 + x ^ 2) * (16 + x ^ 2) / 2 = 100x ^ 2, let t = x ^ 2T ^ 2 + 52T + 576 = 100tt ^ 2-48t + 576 = 0t = 24x

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