It is known that in the triangle ABC, the angle c is equal to 90 degrees, AC is equal to BC, and ad is the bisector of the angle BAC. It is proved that AC + CD = ab

Ah, the first sentence is wrong. Because ad bisects ⊥ BAC, so ⊥ bad = ⊥ CAD, because ⊥ C = ⊥ AED = 90 degrees, ad = ad, so △ ade ≌ ADC (AAS) ⊥ x0d, so CD = De, AC = AE, because ⊥ ABC is isosceles right triangle, so ⊥ B

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