It is known that D and E are the points on the sides BC and AC of equilateral △ ABC, and BD = CE, be and ad intersect at the point F;

It is known that D and E are the points on the sides BC and AC of equilateral △ ABC, and BD = CE, be and ad intersect at the point F;

Because △ ABC is an equilateral triangle and BD = CE
So △ abd ≌ △ BCE
Therefore, CBE = bad
∠AFE=∠FBA+∠BAD=∠FBA+∠CBE=∠ABC=60°