D. E and F are the midpoint of AB, BC and AC respectively. It is proved that triangle ABC is similar to triangle EFD

D. E and F are the midpoint of AB, BC and AC respectively. It is proved that triangle ABC is similar to triangle EFD

Because e and F are the midpoint of AC and ab respectively, EF / / and = 1 / 2BC
Similarly, FD / / and = 1 / 2Ac
Ed / / and = 1 / 2Ab
So, △ ABC is similar to △ EFD