Pythagorean theorem in junior high school If the sides of a right triangle are a, B and the hypotenuse is C, then the relationship between a, B and C can be expressed as

Square of a + square of B = square of C

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1. A question about Pythagorean theorem in junior high school? A door frame (ABCD) is 2m long and 1m wide. Can a 3 m long and 2.2m wide veneer pass through the door frame? Why?
2. Junior high school inverse proportion function + Pythagorean theorem We know that n is a positive integer, P1 (x1, Y1), P2 (X2, Y2) ,P（xn,yn）,… Is the inverse scale function y = K / x, where X1 = 1, X2 = 2 ,xn=n,… Let A1 = x1y1, A2 = x2y2 ,An=xn yn+1,… If A1 = a (a is a nonzero constant), then A1 · A2 · ·The value of an is_______ (expressed by an algebraic expression containing a and N)
3. Pythagorean theorem and all the formulas of geometry Geometric formulas and conversions are all in urgent need
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5. Pythagorean theorem in junior high school A rectangle is twice as long as it is wide The length of its diagonal is 5cm, What is the length of the rectangle? a 2.5cm b （√5）/2cm c 2√5cm d √5cm
6. As shown in the figure, in the isosceles triangle ABC, the angle ACB is equal to 90 degrees, ad is the middle line of the waist BC, CE is perpendicular to ad, AB intersects e, and the angle CDA is equal to the angle EDB
7. As shown in the figure, in the isosceles right triangle ABC, ∠ ACB = 90 °, ad is the middle line on the waist CB, CE ⊥ ad intersects AB with E
8. As shown in the figure, in the isosceles right triangle ABC, ∠ ACB = 90 °, ad is the middle line on the waist CB, CE ⊥ ad intersects AB with E
9. As shown in the figure, ad ∥ BC, ∠ a = ∠ C, be and DF divide ∥ ABC and ∥ CDA equally
10. Known: as shown in the figure, ad ∥ BC, ab ∥ DC, verification: △ ABC ≌ △ CDA
11. There is a 15cm * 13.5cm * 4.5cm box. How long can you put a chopstick? What about a box of size a * b * C? Trigonometric function has not yet learned, with the most basic Pythagorean theorem
12. In △ ABC, points D.E.F are AB.BC.CA To prove that △ ABC is similar to △ EFD
13. As shown in the figure, in the triangle ABC, BC = AB, f is a point on the side of AC, e and D are points on BC and ab respectively, ∠ EFD = a Prove the CEF ∽ AFD of triangle
14. As shown in the figure, ACB = BDC = CED = EFD = 90 degree. (1) how many triangles in the figure are similar to △ ABC. (2) which two triangles in the figure are similar to each other
15. D. E and F are the midpoint of AB, BC and AC respectively. It is proved that triangle ABC is similar to triangle EFD
16. As shown in the figure: in △ EBD, EB = ed, point C is on BD, CE = CD, be ⊥ CE, a is a point on the CE extension line, EA = EC. Try to judge the shape of △ ABC and prove your conclusion
17. As shown in the figure: in △ EBD, EB = ed, point C is on BD, CE = CD, be ⊥ CE, a is a point on the CE extension line, EA = EC. Try to judge the shape of △ ABC and prove your conclusion
18. It is known that the triangle ABC is an equilateral triangle, EC is perpendicular to the plane ABC, BD is perpendicular to the plane ABC, and EC and DB are on the same side of the plane ABC It is known that the triangle ABC is an equilateral triangle, EC is perpendicular to plane ABC, BD is perpendicular to plane ABC, and EC and DB are on the same side of plane ABC, M is the midpoint of EA, CE = 2bd. It is proved that: (1) plane BDM is perpendicular to plane ECA; (2) plane DEA is perpendicular to plane ECA
19. As shown in the figure, △ ABC is an equilateral triangle, BD ⊥ plane ABC, BD ∥ CE, and CE = CA = 2bd, M is the midpoint of EA, find plane DEA ⊥ plane ECA
20. The triangle ABC is an equilateral triangle, CE ⊥ plane ABC, BD ∥ CE, and CE = CA = 2bd, M is the midpoint of EA