As shown in the figure, in the isosceles right triangle ABC, ∠ ACB = 90 °, ad is the middle line on the waist CB, CE ⊥ ad intersects AB with E
As shown in the figure, the \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\cgin △ bed =BE∠GCD=∠BCD=BD,∴△CGD≌△BED(SAS),∴∠CDA=∠EDB.
RELATED INFORMATIONS
- 1. As shown in the figure, ad ∥ BC, ∠ a = ∠ C, be and DF divide ∥ ABC and ∥ CDA equally
- 2. Known: as shown in the figure, ad ∥ BC, ab ∥ DC, verification: △ ABC ≌ △ CDA
- 3. abcd+abc+bcd+cda+dab+ab+bc+cd+da+ac+bd+a+b+c+d=2009 a+b+c+d=? It's urgent,
- 4. Point AOB on a straight line ∠ ABC = 2 / 1 ∠ BOC + 30 ° OE bisection ∠ BOC, what does it mean to find the degree of ∠ BOE in OE bisection 1 / 2 wrong number, ha ha... Pay attention to help me solve the problem
- 5. When ∠ BOC = 60 ° and OE and od are the angular bisectors of ∠ AOC and ∠ BOC, then ∠ EOD = -___ ,∠COE=____ The angular bisector of the BOE is___ .
- 6. As shown in the figure, in △ ABC, the bisector of the outer angle ∠ CBD and ∠ BCE intersects at point O, and it is proved that ∠ BOC = 90 ° - & frac12; ∠ a
- 7. In triangle ABC, ad is perpendicular to BC, CE is perpendicular to AB, ad = 12 cm, CE = 15 cm, AB side is 4 cm shorter than BC side Q: what is the area of triangle ABC in square centimeters?
- 8. Solving triangle: in triangle ABC, B = 2 √ 3, a = 60 ° and a = 3 √ 2 are defined by sine
- 9. In △ ABC, the angles a, B and C are opposite to three sides a, B and C respectively. It is known that a = 5, B = 2 and B = 120 ° to solve the triangle
- 10. In the triangle ABC, we know a = √ 3, B = √ 2, B = 45 degrees, and solve the triangle
- 11. As shown in the figure, in the isosceles right triangle ABC, ∠ ACB = 90 °, ad is the middle line on the waist CB, CE ⊥ ad intersects AB with E
- 12. As shown in the figure, in the isosceles triangle ABC, the angle ACB is equal to 90 degrees, ad is the middle line of the waist BC, CE is perpendicular to ad, AB intersects e, and the angle CDA is equal to the angle EDB
- 13. Pythagorean theorem in junior high school A rectangle is twice as long as it is wide The length of its diagonal is 5cm, What is the length of the rectangle? a 2.5cm b (√5)/2cm c 2√5cm d √5cm
- 14. As shown in the figure, it is known that the radius of the circle on the bottom of the cylinder is 2 π & nbsp; cm, and the height is 2cm. AB and CD are the diameters of the two bottom surfaces respectively, and AD and BC are the generatrix. If a bug starts from point a and crawls from the side to point C, the shortest length of the crawling path is______ &Nbsp; cm
- 15. Pythagorean theorem and all the formulas of geometry Geometric formulas and conversions are all in urgent need
- 16. Junior high school inverse proportion function + Pythagorean theorem We know that n is a positive integer, P1 (x1, Y1), P2 (X2, Y2) ,P(xn,yn),… Is the inverse scale function y = K / x, where X1 = 1, X2 = 2 ,xn=n,… Let A1 = x1y1, A2 = x2y2 ,An=xn yn+1,… If A1 = a (a is a nonzero constant), then A1 · A2 · ·The value of an is_______ (expressed by an algebraic expression containing a and N)
- 17. A question about Pythagorean theorem in junior high school? A door frame (ABCD) is 2m long and 1m wide. Can a 3 m long and 2.2m wide veneer pass through the door frame? Why?
- 18. Pythagorean theorem in junior high school If the sides of a right triangle are a, B and the hypotenuse is C, then the relationship between a, B and C can be expressed as
- 19. There is a 15cm * 13.5cm * 4.5cm box. How long can you put a chopstick? What about a box of size a * b * C? Trigonometric function has not yet learned, with the most basic Pythagorean theorem
- 20. In △ ABC, points D.E.F are AB.BC.CA To prove that △ ABC is similar to △ EFD