Solving triangle: in triangle ABC, B = 2 √ 3, a = 60 ° and a = 3 √ 2 are defined by sine

sinB/b=sinA/a
sinB=bsinA/a=√2/2
B=45°
C=75°
sinC/c=sinA/a
c=asinC/sinA=6+√3

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