In triangle ABC, ad is perpendicular to BC, CE is perpendicular to AB, ad = 12 cm, CE = 15 cm, AB side is 4 cm shorter than BC side Q: what is the area of triangle ABC in square centimeters?

This problem can be used to solve the equation. First of all, the area of the triangle is 1 / 2 of the bottom x height, and the height on the side AB is CE = 15 cm.BC The height of edge is ad = 12cm. Because edge AB is 4cm shorter than edge BC, let edge AB be x and edge BC be (x + 4), then 15x / 2 = (x + 4) 6, x = 16 and SABC = 120cm2

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