In △ ABC, a = 22, a = 30 ° and B = 45 ° are known to solve triangles

∵ a = 30 °, B = 45 °, C = 180 ° - 30 ° - 45 ° = 105 ° from Asina = bsinb, Asina = csinc, B = sinbsina · a = sin45 ° sin30 °× 22 = 2212 × 22 = 4, C = sincsina · a = sin105 ° sin30 °× 22 = 6 + 2412 × 22 = 2 (3 + 1)

RELATED INFORMATIONS

1. 1. In △ ABC, it is known that a = π / 3, a = √ 3, B = 1, a = 4, B = 4 √ 3, a = 30 ° solution, B = 5 √ 3, C = 15, B = 30 ° solution Why can't we get 150 degrees
2. In the triangle ABC, solve the triangle according to the following conditions, two of which are A a=7,b=2,c=8 B a = 10, B = 45 degrees, C = 75 degrees\ C a = 7, B = 5, a = 80 degrees D a = 7, B = 8, a = 45 degrees
3. In triangle ABC, solve the triangle according to the following conditions There are two solutions A、b=10,A=45°,C=75° B、a=60,b=48,C=60° C、a=7,b=5,A=80° D、a=14,b=16,A=45°
4. If the ratio of the length of the two right sides of a right triangle is 2:1 and the length of the hypotenuse is 10cm, then the area of the right triangle is______ ．
5. It is known that the sum of the lengths of two right sides of a right triangle is 10cm (1). When the length of one right side is 4cm, the area of the right triangle is obtained (2). Let
6. The two right sides of a right triangle are 6cm and 8cm respectively. The length of the hypotenuse is 10cm. The area of the right triangle is 5cm______ cm2．
7. The three sides of a right triangle are 6cm 8cm 10cm. The area of the triangle is () cm2, and the height of the hypotenuse is (0cm)
8. Is it easy to solve the problem with the help of the above diagram? Please use this method to solve the following problem. (first draw a picture) an isosceles right triangle, the length of the hypotenuse is 10cm. What is the area of this triangle?
9. Right triangle, the length of each side is 6cm.8cm.10cm. What is the area of the triangle and the height of the hypotenuse
10. The sum of the two right sides of a right triangle is 14 cm, and the area is 24 cm 2
11. Solve triangle problem in triangle ABC: a = 7, B = 5, a = 80 degrees, solve triangle
12. In △ ABC, a = 30 °, B = 120 ° and B = 5 are known to solve triangles
13. In the triangle ABC, we know a = √ 3, B = √ 2, B = 45 degrees, and solve the triangle
14. In △ ABC, the angles a, B and C are opposite to three sides a, B and C respectively. It is known that a = 5, B = 2 and B = 120 ° to solve the triangle
15. Solving triangle: in triangle ABC, B = 2 √ 3, a = 60 ° and a = 3 √ 2 are defined by sine
16. In triangle ABC, ad is perpendicular to BC, CE is perpendicular to AB, ad = 12 cm, CE = 15 cm, AB side is 4 cm shorter than BC side Q: what is the area of triangle ABC in square centimeters?
17. As shown in the figure, in △ ABC, the bisector of the outer angle ∠ CBD and ∠ BCE intersects at point O, and it is proved that ∠ BOC = 90 ° - & frac12; ∠ a
18. When ∠ BOC = 60 ° and OE and od are the angular bisectors of ∠ AOC and ∠ BOC, then ∠ EOD = -___ ,∠COE＝____ The angular bisector of the BOE is___ .
19. Point AOB on a straight line ∠ ABC = 2 / 1 ∠ BOC + 30 ° OE bisection ∠ BOC, what does it mean to find the degree of ∠ BOE in OE bisection 1 / 2 wrong number, ha ha... Pay attention to help me solve the problem
20. abcd+abc+bcd+cda+dab+ab+bc+cd+da+ac+bd+a+b+c+d=2009 a+b+c+d=? It's urgent,