Indefinite integral of arctanx / x ^ 2

Let u = arctanx, V '= 1 / x ^ 2, u' = 1 / (1 + x ^ 2), v = - 1 / x, the original formula = - (arctanx) / x + ∫ DX / [x (1 + x ^ 2)] = - (arctanx) / x + ∫ (- x) DX / (1 + x ^ 2) + ∫ DX / x = - (arctanx) / X - (1 / 2) ∫ D (1 + x ^ 2) + ∫ DX / x = - (arctanx) / X - (1 / 2) ln (1 + x ^ 2) + ln

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