(1) Given that the definition field of function f (x) = LG (a (the square of x) + ax + 1) is r, the value range of real number a is obtained; (2) given that the value range of function f (x) = LG (a (the square of x) + ax + 1) is r, the value range of real number a is obtained;

(1) Given that the definition field of function f (x) = LG (a (the square of x) + ax + 1) is r, the value range of real number a is obtained; (2) given that the value range of function f (x) = LG (a (the square of x) + ax + 1) is r, the value range of real number a is obtained;

one
The domain of the function f (x) = LG (a (the square of x) + ax + 1) is r
That is, a (the square of x) + ax + 1 is always greater than zero
Just a > = 0
The discriminant is less than zero
The solution is 0

Elden Ring Premiere

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