Variance of a sample x1, X2, X3, X4 S^=1/4[(X1-3)^+(X2-3)^+(X3-3)^+(X4-3)^]=13 Find the sum of squares of the sample data

The variance formula is transformed as follows
S^=13*4=(X1-3)^+(X2-3)^+(X3-3)^+(X4-3)^
52=X1^-6X1+9+X2^-6X2.X4^-6X4+9
52=(X1^+X2^+X3^+X4^)-6(X1+X2+X3+X4)+4*9
Because the average of this set of data is 3, the sum of the data is 12
52=(X1^+X2^+X3^+X4^)-6*12+36
X1^+X2^+X3^+X4^=52+72-36
X1^+X2^+X3^+X4^=88
It should be like this. No, ask me again

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