X^2 dy/dx=2y^2+yx Find the original function. How to do ah. Urgent

Let y = UX, then x ^ 2 (XDU + UDX) / DX = 2 (UX) ^ 2 + UX ^ 2 reduce x ^ 2
(XDU + UDX) / DX = 2 (U) ^ 2 + U so (XDU) / DX = 2 (U) ^ 2
Then you should know, find out the expression of u with respect to x, and then y = UX OK

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