Given the set M = {y ∈ r y = x & # 178;}, n = {y ∈ R x & # 178; + Y & # 178; = 4}, then m ∩ n = a {[- 1,1}, [1] Given the set M = {y ∈ R, y = x & # 178;}, n = {y ∈ R, X & # 178; + Y & # 178; = 4}, then m ∩ n = 1 A{【﹣1,1},【1,1】} B{1} C{x ﹣2≤x≤2} D{x 0≤x≤2} Given that a = {1,3}, B = {x [x-4] [x-a] = 0}, if the sum of all elements in a ∪ B is 8, then the set of a is Let x = 3-5 times 1 / 6 of radical, y = 3 + radical 6 π, z = 2 under radical 3 + 2 under radical 3 + radical 3, set M = {m m = a + B radical 6, a ∈ Q, B ∈ Q} then the relation between X, y, Z and set M is

Given the set M = {y ∈ r y = x & # 178;}, n = {y ∈ R x & # 178; + Y & # 178; = 4}, then m ∩ n = a {[- 1,1}, [1] Given the set M = {y ∈ R, y = x & # 178;}, n = {y ∈ R, X & # 178; + Y & # 178; = 4}, then m ∩ n = 1 A{【﹣1,1},【1,1】} B{1} C{x ﹣2≤x≤2} D{x 0≤x≤2} Given that a = {1,3}, B = {x [x-4] [x-a] = 0}, if the sum of all elements in a ∪ B is 8, then the set of a is Let x = 3-5 times 1 / 6 of radical, y = 3 + radical 6 π, z = 2 under radical 3 + 2 under radical 3 + radical 3, set M = {m m = a + B radical 6, a ∈ Q, B ∈ Q} then the relation between X, y, Z and set M is

(1) M = {y ∈ R | y = x & # 178;} n = {y ∈ R | X & # 178; + Y & # 178; = 4} X & # 178; + Y & # 178; = 4Y & # 178; + y-4 = 0y = [- 1 ± √ (1 + 16)] / 2 = (- 1 ± √ 17) / 2, so m ∩ n = {(- 1 - √ 17) / 2, (- 1 + √ 17) / 2} there is no matching option. Is there a wrong set? Is it what I wrote above? Because you wrote