Finding the original function of (SiNx) ^ 4 We can only use the exchange method

The primitive function of (SiNx) ^ 4
=1/4∫{[1-cos2x]^2}d(x)
=1/4∫(1-2cos2x+cos^2 2x) dx
=1/4∫dx - 1/4∫cos2x d(2x) + 1/4 ∫(cosx)^2 2xdx
=3/8x-1/4sin2x+1/32sin4x+C

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