Given that a and B are two of the equations x ^ 2 + (M + 2) x + 1 = 0, then the value of (a ^ 2 + Ma + 1) (b ^ 2 + MB + 1) is

It is concluded that a and B are two parts of the equation x ^ 2 + (M + 2) x + 1 = 0
a^2+ma+2a+1=0
b^2+mb+2b+1=0
therefore
a^2+ma+1=-2a
b^2+mb+1=-2b
Then (a ^ 2 + Ma + 1) (b ^ 2 + MB + 1) = 4AB = 4 * 1 = 4 (because AB = 1 / 1 = 1)

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