It is known that the sequence {an} is the arithmetic sequence, and the sequence {BN} is the proportional sequence, whose common ratio Q ≠ 1 and Bi ＞ 0 (I = 1, 2, 3,...) If A1 = B1, a11 = B11, then () A. A6 = b6b. A6 > b6c. A6 < b6d. A6 > B6 or A6 < B6

From the meaning of the title, we can get a1 + a11 = B1 + B11 = 2A6. ∵ common ratio Q ≠ 1, Bi > 0, ∵ B1 + B11 > 2B1 · B11 = 2b6, ∵ 2A6 > 2b6, that is & nbsp; A6 > B6, so we choose B

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