As shown in the figure, it is known that in △ ABC, D is the midpoint of AB, e is the point on AC, and ∠ Abe = ∠ BAC, EF ‖ AB, DF ‖ be. Please guess the relationship between DF and AE, and explain the reason

As shown in the figure, it is known that in △ ABC, D is the midpoint of AB, e is the point on AC, and ∠ Abe = ∠ BAC, EF ‖ AB, DF ‖ be. Please guess the relationship between DF and AE, and explain the reason

DF = AE for the following reasons: ∵ EF ∥ AB, DF ∥ be ∥ quadrilateral dbef is a parallelogram, ∵ DF = be ∥ Abe = ∥ BAC, ∥ AE = be ∥ DF = AE